Opening scenario
Longest Substring Without Repeating Characters (LC 3). Given a string
s, return the length of the longest substring with no repeated characters.s = "abcabcbb"→3("abc"). Follow-up you should expect: Minimum Window Substring (LC 76) — the smallest substring ofsthat contains every character oft(with multiplicity).
LC numbers identify LeetCode problems.
A substring is contiguous. In LC 76, “with multiplicity” means that t = "AAB" requires at least two As and one B; return "" if no window qualifies. The template also returns "" for empty s or t. As the right boundary advances, which information can you update instead of recomputing it?
Question progression
Q1 — What is the brute force, and what is it recomputing?
Question: How do you find the longest no-repeat substring naively, and what is the cost?
Reasoning: Enumerate every start i, extend j until you hit a repeat — O(n^2) substrings, and…
In the full tutorial
- Canonical Template
- Complexity
- Pattern Recognition Signals
- Practice Set
- Pitfalls
- Variations
- Closing: When to Reach for This